Python3.6.7の予約語を全部使ってみる3(lambdaを使って素数の調査)

今回新規で使ったもの(lambda None True not and False import from assert)

p = lambda x:print(chr(10)+chr(13)+x)

p("#lambda 2倍")
hitBiscuit = lambda x:x*2
print(hitBiscuit(2))

p("#配列で2倍")
hitBiscuit2 = lambda x:[x,x]
print(hitBiscuit2(2))
print(hitBiscuit2(hitBiscuit2(2)))

p("#None")
a=[]
print(a is None)
print(a)
a=None
print(a is None)
print(a)

p("#1〜xのrange")
range2=lambda x:[i for i in range(1,x+1)]
print(sum(range2(10)))

p("#True not and　素数")
sosu = lambda x:x>=2 and len([i for i in range(2,x) if x%i==0])==0
s=[]
for i in range2(100):
    if sosu(i)==True:s.append(i)
print(s)
ns=[]
for i in range2(100):
    if not(sosu(i)==True):ns.append(i)
print(ns)

p("#False　素数でない数の割合1")
c=0
for i in range2(1000):
    if sosu(i)==False:c+=1
print("1000まで",c/1000)

#1行にしてみる
print("10000まで", sum( [1 for i in range2(10000) if sosu(i)==False] ) /10000)

p("#import from　素数でない数の割合2")
from random import *
c=0
for i in range2(1000):
    if sosu(randint(1,10000))==False:c+=1
print("10000までランダム抽出",c/1000)

#1行にしてみる
print("100000までランダム抽出",sum( [1 for i in range2(1000) if sosu(randint(1,100000))==False] )/1000)

p("#assert")
assert 1==2,"エラーしてみる"