![](https://blogimg.goo.ne.jp/user_image/63/41/1678baa45a15d12ec499905de84c792f.png)
[Set 12,812,904 on Mr. Cube root]
[Japanese]
Following the last time, today's example is about actual solution of Cube root using abacus.
Today's example is simple - basic 1/3-multiplication table method, root is 3-digits case. You can check the Index page of all articles.
Cube root methods: Triple-root method, constant number method, 3a^2 method, 1/3-division method, 1/3-multiplication table method, 1/3-multiplication table alternative method, Multiplication-Subtraction method, 3-root^2 method, Mixing method, Exceed number method, Omission Method, etc.
Abacus steps to solve Cube root of 12,812,904
(Answer is 234)
"1st group number" is the left most numbers in the 3-digits groups of the given number for cube root calculation. Number of groups is the number of digits of the Cube root.
12,812,904 -> (12|812|904): 12 is the 1st group number. The root digits is 3.
![](https://blogimg.goo.ne.jp/user_image/2c/57/1217710213c1aa376042e5c0c9795b74.png)
Step 1: Place 12812904 on HIJKLMNO.
![](https://blogimg.goo.ne.jp/user_image/39/61/02eb941d32431f004702b93f665af9ba.png)
Step 2: The 1st group is 12.
![](https://blogimg.goo.ne.jp/user_image/06/ca/fa0bc17c004819ac351d5eea634338f7.png)
Step 3: Cube number ≦ 12 is 8=2^3. Place 2 on C as the 1st root.
![](https://blogimg.goo.ne.jp/user_image/29/56/8c5330735383a174f9c902a435836211.png)
Step 4: Subtract 2^3 from the 1st group 12. Place 12-2^3=04 on HI.
![](https://blogimg.goo.ne.jp/user_image/5b/62/eec573bb73f51a55e0492b1ae5f8fd18.png)
Step 5: Focus on 4812904 on IJKLMNO.
![](https://blogimg.goo.ne.jp/user_image/1e/5b/06d7a3931ba9b66dc42d9fdee27bd845.png)
Step 6: Divide 4812904 by 3. Place 4812904/3=16043013 on IJKLMNOP.
![](https://blogimg.goo.ne.jp/user_image/29/d7/dca94f2bef99b39a0cb9fceb0e867a86.png)
Step 7: Focus on 16 on HI.
![](https://blogimg.goo.ne.jp/user_image/1f/d4/7edd19c5add10bf869731f1ad2ee3719.png)
Step 8: Repeat division by current root 2 until 4th digits next to 1st root. 16/2=8 remainder 0. Place 8 on F.
![](https://blogimg.goo.ne.jp/user_image/43/0d/a4508ff32f5049e61c7b9253a076a673.png)
Step 9: Place remainder 00 on IJ.
![](https://blogimg.goo.ne.jp/user_image/43/de/eec8335cd9d88353e3a8335b0a0d989a.png)
Step 10: Divide 8 on F by current root 2. 8/2=3 remainder 2
![](https://blogimg.goo.ne.jp/user_image/09/34/237cb7230f6cd3af3a8b58f0171258ec.png)
Step 11: Place 3 on D as 2nd root.
![](https://blogimg.goo.ne.jp/user_image/2e/1e/0b501b9ceb8518e111b04b51bb213bb3.jpg)
Step 12: Place 2 on F.
![](https://blogimg.goo.ne.jp/user_image/2e/1e/0b501b9ceb8518e111b04b51bb213bb3.jpg)
Step 13: Subtract 2nd root^2 from 20 on EF. 20-3^2=11
![](https://blogimg.goo.ne.jp/user_image/31/48/58eaae434c2f6643b62eff96d7251f4b.png)
Step 14: Place 11 on FG.
![](https://blogimg.goo.ne.jp/user_image/7d/5f/2f6ad3334197f6f72c95290e0bac14ca.png)
Step 15: Add 1st root x remainder 11 to 00 on JK. 11X2+0=22
![](https://blogimg.goo.ne.jp/user_image/00/e0/0dc95f6026960fb0bd9ac544b12afa5b.png)
Step 16: Place 00 on JK.
![](https://blogimg.goo.ne.jp/user_image/72/24/3c3132070dc322aff4aebb83c888de39.png)
Step 17: Subtract 2nd root/3 from 224 on JKL. 224-3^3=215
![](https://blogimg.goo.ne.jp/user_image/33/ac/716b8f521d9513fb81c1f2b9d9be0223.png)
Step 18: Place 215 on JKL.
![](https://blogimg.goo.ne.jp/user_image/4c/a0/20d0611ebd735cdbc351c8fc8fbebce3.png)
Step 19: Clear 11 on FG. Place 00 on FG.
![](https://blogimg.goo.ne.jp/user_image/78/90/23151fdc08fc007a5a100453e30c4b0a.png)
Step 20: Divide by current root 23 from NOP.
![](https://blogimg.goo.ne.jp/user_image/5d/7c/0ebccc33081d586785af4597e1bc6f93.png)
Step 21: 215/23=9 remainder 8. Place 9 on G.
![](https://blogimg.goo.ne.jp/user_image/44/19/b1e0025d8e92f824e84743ff5b3f3e5b.png)
Step 22: Place 008 on JKL.
![](https://blogimg.goo.ne.jp/user_image/6f/89/602090b950126cf81de78501e46dc02a.png)
Step 23: 83/23=3 remainder 14. Place 3 on H.
![](https://blogimg.goo.ne.jp/user_image/18/72/31542f869497b1cba1f93677e0052cd9.png)
Step 24: Place 14 on LM.
![](https://blogimg.goo.ne.jp/user_image/16/c2/d965e59252ff8bd1a72b9449881e8d9a.png)
Step 25: 140/23=6 remainder 2. Place 6 on I.
![](https://blogimg.goo.ne.jp/user_image/22/fb/9190875ecaabd1c3956d523f21f43628.png)
Step 26: Place 002 on LMN.
![](https://blogimg.goo.ne.jp/user_image/6e/41/dcb4ff6ce1a21ade4a2bbc0c4b4d1ff7.png)
Step 27: Divide 93 on GH by crrent root 23. 93/23=4 remainder 1
![](https://blogimg.goo.ne.jp/user_image/19/e2/e34eec7cd5f1a454a7207f2766f87a03.png)
Step 28: Place 4 on E as 3rd root.
![](https://blogimg.goo.ne.jp/user_image/64/5c/9901d5037f4d071f4ad36bce7b689222.png)
Step 29: Place 01 on GH.
![](https://blogimg.goo.ne.jp/user_image/68/e2/71cb0d58fdcbe95d45e038a114a79f2b.png)
Step 30: Subtract 3rd root^2 from 16 on HI. 16-4^2=0
![](https://blogimg.goo.ne.jp/user_image/49/00/ebbfa33b28853e2d8a5298b74ea0c2db.png)
Step 31: Place 00 on HI.
![](https://blogimg.goo.ne.jp/user_image/52/d5/4e656f7991b178a0ff5b99dfe97a1e79.png)
Step 32: Subract 3rd root/3 from 21.3 on NOP. 21.3-4^3/3=0
![](https://blogimg.goo.ne.jp/user_image/63/58/a479c9185bcd21fa58192465b461bc2f.png)
Step 33: Place 000 on NOP.
![](https://blogimg.goo.ne.jp/user_image/1d/95/be69ece80dee4d6098a63cbc74f88b23.png)
Step 34: Cube root of 12812904 is 234.
![](https://blogimg.goo.ne.jp/user_image/6e/fc/94b582d841e3e8b76f07b57c0b48b54c.png)
Final state: Answer 234
Abacus state transition. (Click to Zoom)
![](https://blogimg.goo.ne.jp/user_image/38/92/24bc4169778a9e5b5575b75417648c05.jpg)
![](https://blogimg.goo.ne.jp/user_image/50/2d/4f68c476dd9e6498b46761467397fc8d.jpg)
Next article is also 1/3-multiplication table method.
Related articles:
How to solve Cube root of 1729.03 using abacus? (Feynman v.s. Abacus man)
https://blog.goo.ne.jp/ktonegaw/e/cff5d6e7ecaa07230b9cc7af10b23aed
Index: Square root and Cube root using Abacus
https://blog.goo.ne.jp/ktonegaw/e/f62fb31b6a3a0417ec5d33591249451b
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