TeXソースファイル

これがソースファイル。一旦ブログの編集画面にコピペ。
ここから、パソコンにコピペして編集すればよい。
\documentclass{article}
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%\usepackage[pdftex]{graphicx}
% Allow the usage of utf8 characters
\usepackage[utf8]{inputenc}
\usepackage{amsmath}
% Start the document
\begin{document}

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\section{}



$E=E_0\sin \omega t$

\vspace{1cm}

$L\displaystyle \frac{dI}{dt}+RI=E_0\sin \omega t$

\vspace{24pt}

$I(t)=A\sin(\omega t-\varphi)$

\vspace{24pt}

$(LA\omega\cos\varphi-RA\sin\varphi)\cos\omega t%
+(LA\omega\sin\varphi+RA\cos\varphi-E_0)\sin\omega t=0$


\vspace{24pt}

$L\omega A\cos\varphi-RA\sin\varphi=0$

\vspace{2pt}

$L\omega A\sin\varphi+RA\cos\varphi-E_0=0$

\vspace{24pt}

$A\cos\varphi=\displaystyle \frac{R}{L^2\omega^2+R^2}E_0$
\quad$\cdots$(1)

\vspace{2pt}

$A\sin\varphi= \dfrac{L\omega}{L^2\omega^2+R^2}E_0$
\quad$\cdots$(2)

\vspace{24pt}

$(1)^2+(2)^2\ \to \ A^2=\dfrac{E_0^2}{R^2+L^2\omega^2}$

\vspace{24pt}


$A=\dfrac{E_0}{\sqrt{R^2+L^2\omega^2}}=I_{max}$

\vspace{24pt}

$\tan\varphi=\dfrac{A\sin\varphi}{A\cos\varphi}
=\dfrac{L\omega}{R}$

\vspace{24pt}

$I(t)=\dfrac{E_0}{\sqrt{R^2+L^2\omega^2}}\sin(\omega t-\varphi)$


% Uncomment the following two lines if you want to have a bibliography
%\bibliographystyle{alpha}
%\bibliography{document}

\end{document}